Answer:
The relation to find base is,
![base=(area\ of\ the \ parallelogram)/(height)=(86)/(12)=7.16\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lxnb7r2cwask1im4nxtenht13q22dv4bk6.png)
Explanation:
Given
Area of the parallelogram
![=86\ cm^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5qbc8yppxbyma60c8au8cnqt7it3xa2a5e.png)
Height of the parallelogram
![=12\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7i8blydtv2baqlicw83bdez89ry6zpzr3l.png)
We know that the area of the parallelogram
![=base* height](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fk2rrk6wflery1qeh1krldghulno9o1m1y.png)
So
To find base we have to divide the height on both sides of the equation.
![base=(area\ of\ the \ parallelogram)/(height)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7d9ykppstws28hxqlmt2s2jxejfe5e1wzl.png)
Plugging the values.
![base=(86)/(12) =7.1\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m9f4k0p5em5xlrfbw9zke3uo8jfk9wxqak.png)
So the base in terms of area of the parallelogram and its height is
![b=(area)/(height) =(86)/(12)=7.16\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f4p12k8d0xggqmrs9d1mrgc6zgcodk63qx.png)