Question

The velocity of a car increases from +2.0 m/s to +16.0 m/s in a time period of 3.5 s. What was the average acceleration?

Answer 1

The average acceleration is
`4\ m/s^2`

Step-by-step explanation:

Motion With Constant Acceleration

It's a type of motion in which the velocity of an object changes uniformly in time. If only the magnitudes are considered, then the equation that describes the change of speeds is:

`v_f=v_o+at`

Where:

a = acceleration

vo = initial speed

vf = final speed

t = time

The velocity (magnitude or speed) of a car increases from v0=2 m/s to vf=16 m/s in t=3.5 s. We can calculate the acceleration by solving for a:

`\displaystyle a=(v_f-v_o)/(t)`

`\displaystyle a=(16-2)/(3.5)`

`\displaystyle a=(14)/(3.5)`

`\boxed{a = 4\ m/s^2}`

The average acceleration is
`4\ m/s^2`