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An oscillating block-spring system has a mechanical energyof 1.00 J and amplitude of 10.0 cm and a maximum speed of 1.20m/s. Find (a) the spring constant and (b) the mass of theblock, and (c) the frequency of oscillation.

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Answer:

Step-by-step explanation:

Given

Mechanical Energy of Spring-Block system is 1 J

Maximum Amplitude is
A=10 cm

maximum speed
v_(max)=1.2 m/s

Suppose
x=A\sin \omega tbe general equation of motion of spring-mass system

where A=max amplitude


\omega=Natural frequency of oscillation

t=time


v_(max)=A\omega =1.2


0.1\cdot \omega =1.2


\omega =12 rad/s

maximum kinetic Energy must be equal to total Mechanical Energy when spring is un deformed i.e. at starting Position


(1)/(2)mv_(max)^2=1


m=(2)/(1.2^2)=(2)/(1.44)=1.38 kg

Also
\omegais also given by


\omega =\sqrt{(k)/(m)}


k=\omega ^2\cdot m

where k= spring constant


k=12^2\cdot 1.38


k=200 N/m

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