Question

What force, in newtons, must you exert on the balloon with your hands to create a gauge pressure of 62.5 cm H2O, if you squeeze on an effective area of 51 cm2? Assume the pressure in the balloon is one atmosphere before you squeeze.

Answer 1

Answer:54.70 N

Step-by-step explanation:

Given

Gauge Pressure of
`62.5 cm of H_2O`

i.e.
`h=62.5 cm =0.625 m`

Effective area
`A=51 cm^2`

initial Pressure
`= 1 atm=101.325 kPa`

Gauge Pressure
`P=\rho gh`

`\rho =density\ of\ water =1000 kg/m^3`

`P_(gauge)=1000* 9.8* 0.625=5.937 kPa`

Force creates a pressure of
`P_1` which will be equal to Gauge Pressure

`P_1=(F)/(A)`

`P_1=P_(gauge)`

`(F)/(A)=5.937 kPa`

`F=5.937* 51* 10^(-4)* 10^3`

`F=30.27 N`