Answer: 6
Explanation:
Let S= Total colleges
A = colleges are expensive.
B= colleges are far from home( more than 200 miles away).
Given : n(S)= 20
n(A)=8
n(B)=8
n(A∩B) =2
Then, the number of college that are not expensive and within 200 miles from home :-
![n(A'\cap B')=n(S)-n(A\cup B)\\\\=20-(n(A)+n(B)-N(A\cap B))\ \ [\because\ n(A\cup B)=n(A)+n(B)-N(A\cap B)]\\\\=20-(8+8-2)\\\\=20-14=6](https://img.qammunity.org/2020/formulas/mathematics/college/n78vh4e0v8oubq8qs99xrgbm8qxq31edik.png)
i.e. the number of college that are not expensive and within 200 miles from home=6
Hence, the number of possible selections are 6 .