To solve this problem it is necessary to apply the concepts related to density in relation to mass and volume for each of the states presented.
Density can be defined as
![\rho = (m)/(V)](https://img.qammunity.org/2020/formulas/physics/middle-school/n5l1nt5eoo6mhavcn1aunaqrew98hzfkvf.png)
Where
m = Mass
V = Volume
For state one we know that
![\rho_1 = (m_1)/(V)](https://img.qammunity.org/2020/formulas/engineering/college/zoktgqz31tdgdyrweg9w7g16v5xa2748kt.png)
![m_1 = \rho_1 V](https://img.qammunity.org/2020/formulas/engineering/college/32w4ecx6ioh5srtfxx9sqa0d0bcmw9qtqs.png)
![m_1 = 1.18*1](https://img.qammunity.org/2020/formulas/engineering/college/wice86yy5t9sfkh0c79b22vymd9v4d0wvr.png)
![m_1 = 1.18Kg](https://img.qammunity.org/2020/formulas/engineering/college/yu9sq2fowsdez1cmrhyop193rdudh9jj96.png)
For state two we have to
![\rho_2 = (m_2)/(V)](https://img.qammunity.org/2020/formulas/engineering/college/jmabgwssepfbh2evwhaugve6tv9q3hqiv2.png)
![m_2 = \rho_2 V](https://img.qammunity.org/2020/formulas/engineering/college/nn6309yeyfbcyfuelgdac3h7cfz0z412cj.png)
![m_1 = 7.2*1](https://img.qammunity.org/2020/formulas/engineering/college/c7ut4mmovdywy38b2d2a1tmhae6ryce2rq.png)
![m_1 = 7.2Kg](https://img.qammunity.org/2020/formulas/engineering/college/dngqjgiwtvis5kdk905fz20e8asfdu1pz5.png)
Therefore the total change of mass would be
![\Delta m = m_2-m_1](https://img.qammunity.org/2020/formulas/engineering/college/f0u91okrynxv8sws9y0dmsx9sec6lg2wzy.png)
![\Delta m = 7.2-1.18](https://img.qammunity.org/2020/formulas/engineering/college/mmke6svcqj8g01eheuhys2b4vsxv64qt48.png)
![\Delta m = 6.02Kg](https://img.qammunity.org/2020/formulas/engineering/college/nr62zc3dzdveac0vda4vy434a082wydpbb.png)
Therefore the mass of air that has entered to the tank is 6.02Kg