Question

A gaseous mixture contains 434.0 Torr H 2 ( g ) , 434.0 Torr H2(g), 389.9 Torr N 2 ( g ) , 389.9 Torr N2(g), and 77.9 Torr Ar ( g ) . 77.9 Torr Ar(g). Calculate the mole fraction, χ , χ, of each of these gases.

Answer 1

H₂: 0.48, N₂: 0.43; Ar: 0.09

Step-by-step explanation:

First of all, sum all the pressures to know the total pressure in the mixture.

434 Torr + 389.9 Torr + 77.9 Torr = 901.8 Torr

Mole fraction = Pressure gas / Total Pressure

Mole Fraction H₂: 434 Torr /901.8 Torr = 0.48

Mole Fraction N₂: 389.9 /901.8 Torr =0.43

Mole Fraction Ar: 77.9 /901.8 Torr = 0.09

Remember: SUM OF MOLE FRACTION = 1