Question

A 250 mL container of CO2 exerting a pressure of 1.00 atm is connected through a valve to a 500 mL container of O2 exerting a pressure of 2.00 atm.

When the valve is opened, the gases mix, forming a 750 mL mixture of CO2 and O2.

What is the total pressure of this mixture?

Answer 1

Step-by-step explanation:

The given data is as follows.

`P_(1)` = 1 atm,
`P_(2)` = 2 atm

`V_(1)` = 250 ml,
`V_(2)` = 500 ml

Total volume =
`V_(1) + V_(2)` = 750 ml

Therefore, total pressure will be as follows.

`P_(total) V_(total) = P_(1)V_(1) + P_(2)V_(2)`

`P_(total) = (P_(1)V_(1) + P_(2)V_(2))/(V_(total))`

=
`(1 atm * 250 ml + 2 atm * 500 ml)/(750 ml)`

= 1.66 atm

Thus, we can conclude that total pressure of the given mixture is 1.66 atm.