Question

The following reaction is found to be at equilibrium at 25 celcius: 2SO3--->O2 + 2SO2 + 198kJ/mol. If the value for Kc at 25 celcius is 8.1, are the products or reactants favored and how much?

A.) Reactants are strongly favored
B.) Reactants are weakly favored
C.) Products are strongly favored
D.) Products are weakly favored

Answer 1

D.) Products are weakly favored

Step-by-step explanation:

For the reaction:

2SO₃ ⇄ O₂ + 2SO₂ + 198kJ/mol

The kc is defined as:

kc = [O₂] [SO₂]² / [SO₃]²

As the kc is 8,1:

8,1 [SO₃]² = [O₂] [SO₂]²

The products are favored 8,1 times. This is a weakly favored because the usual kc are in the order of 1x10⁴. Thus, right answer is:

D.) Products are weakly favored

I hope it helps!