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If the surface temperature of that person's skin is 30∘C (that's a little lower than healthy internal body temperature because your skin is usually a little colder than your insides), what is the total power that person will radiate? For now, assume the person is a perfect blackbody (so ϵ=1).

1 Answer

5 votes

Answer:


E=477.92\ W.m^(-2)

Step-by-step explanation:

Given that:

Absolute temperature of the body,
T=273+30=303\ K

  • emissivity of the body,
    \epsilon=1

Using Stefan Boltzmann Law of thermal radiation:


E=\epsilon. \sigma.T^4

where:


\sigma =5.67* 10^(-8)\ W.m^(-2).K^(-4) (Stefan Boltzmann constant)

Now putting the respective values:


E=1* 5.67* 10^(-8)* 303^4


E=477.92\ W.m^(-2)

User Ajreal
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