Question

Which graph shows the solution to the system of linear inequalities?

y < 2x – 5

y > –3x + 1

On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the right of the line is shaded. The second dashed line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the right of the line is shaded.
On a coordinate plane, 2 straight lines are shown. The first dashed line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the right of the line is shaded. The second solid line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the right of the line is shaded.
On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the left of the line is shaded. The second dashed line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the left of the line is shaded.
On a coordinate plane, 2 straight lines are shown. The first dashed line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the left of the line is shaded. The second solid line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the left of the line is shaded. HELP ME PLEASE HURRY

Answer 1

None of the Original alternatives above.

Explanation:

The Graphic solution to this system of inequalities is the common shaded area of both inequalities.(Green +Blue)

So the answer would be, a A with a little adjustment on y≥-3x+1 and y <2x-5

On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0,1) and (-1, 2). Everything to the right of the line is shaded. The second dashed line has a positive slope and goes through (0, -5) and (2, -1). Everything to the right of the line is shaded.

Answer 2

none of the above

Explanation:

Neither of the two inequalities include the "or equal to" case, so both boundary lines will be dashed. None of your descriptions match that condition.

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The closest is ... (the first one)

On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the right of the line is shaded. The second dashed line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the right of the line is shaded.

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If both lines were dashed, this would be correct (or if the second inequality is actually y ≥ -3x +1).