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Please help! The question is in the picture!

Please help! The question is in the picture!-example-1
User Kibria
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1 Answer

2 votes

Answer:

OPTION A and OPTION C

Explanation:

OPTION A:


$ (1)/(5)x - 10 $ and
$ (1)/(5)(x - 50) $

Consider
$ (1)/(5)(x - 50) = (x)/(5) - (50)/(5) $

This is equal to
$ (1)/(5)x - 10 $.

This is exactly the first expression. So, we say both expressions are equivalent.

OPTION B:


$ (1)/(3) x - 6 $ and
$ - (1)/(3)(3x  + 18) $

Distributing
$ -(1)/(3) $ to
$ (3x + 18) $ we get:


$ (-x)/(3) + (-18)/(3) $


$ -x - 6

This is not equivalent to the first expression.

OPTION C:


$ (1)/(2)x + 8 $ and
$ (1)/(2)(x + 16) $


$ (1)/(2)(x + 16) = (x)/(2) + (16)/(2) $


$ \implies (1)/(2)x + 8 $

This is exactly the first expression. So, we say the expressions are equal.

We apply similar techniques to OPTION D and OPTION E. Note that the expressions are not equal in both the options.

User Dmytro Serdiuk
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