Answer:
The mean free path is
![0.0000373631 m](https://img.qammunity.org/2020/formulas/chemistry/college/v13iwq95gutqgmol5ilcypekbdvnrvy6cy.png)
Step-by-step explanation:
The formula for mean free path is :
λ =
![(V)/(√(2)\pi d^(2)N )](https://img.qammunity.org/2020/formulas/chemistry/college/l16yrjuiq2658g0uz01kelw6rejy68zrp9.png)
where,
λ - is the mean free path distance
V - volume of the gas
d - the diameter of the molecule
N - number of molecules.
now ,
density
=
=
;
mass of the gas = (number of molecules)
(mass of one molecule) ;
as it's atomic hydrogen
![M = N*m \\m=1.66*10^(-24)\\M=N*1.66*10^(-24)](https://img.qammunity.org/2020/formulas/chemistry/college/ajve2amojnvyjzuw2c3m4nqqilbgglogns.png)
∴
=
![(N*1.66*10^(-24))/(V)](https://img.qammunity.org/2020/formulas/chemistry/college/b00x3avk7ualj6dgyvmaxp64kqk0bi2cs0.png)
∴
![(V)/(N*1.66*10^(-24)) = (1)/( D)](https://img.qammunity.org/2020/formulas/chemistry/college/s27wadligwspffwrkh7uq0lblba4mxxnjq.png)
⇒ λ =
![(1)/(√(2)\pi d^(2)D )](https://img.qammunity.org/2020/formulas/chemistry/college/iule407chxika3r90h5sybtem3q6e1g73j.png)
⇒ λ =
![(1.66*10^(-24))/(√(2)\pi (100*10^(-12))^(2)*1 )](https://img.qammunity.org/2020/formulas/chemistry/college/k4m8zsn65tr0mviuv4afw8fahn00ua3c68.png)
⇒ λ =
![0.0000373631 m](https://img.qammunity.org/2020/formulas/chemistry/college/v13iwq95gutqgmol5ilcypekbdvnrvy6cy.png)