Question

How do i put this in slope-intercept form. passes through 2,-2 and 4,-1​

Answer 1

`\large\boxed{y=(1)/(2)x-3}`

Explanation:

The slope-intercept form of an equation of a line:

`y=mx+b`

m - slope

b - y-intercept

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

We have two points (2, -2) and (4, -1).

Substitute:

`m=(-1-(-2))/(4-2)=(-1+2)/(2)=(1)/(2)`

Put the value of a slope and the coordinates of the point (2, -2) to the equation of a line:

`-2=(1)/(2)(2)+b`

`-2=1+b` subtract 1 from both sides

`-3=b\to b=-3`

Finally:

`y=(1)/(2)x-3`