How do i put this in slope-intercept form. passes through 2,-2 and 4,-1

Question

asked Aug 18, 2020 100k views

1 Answer

Raj More · Answer 1 · 2020-08-24T04:07:01+0000

Answer:

$\large\boxed{y=(1)/(2)x-3}$

Explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=(y_2-y_1)/(x_2-x_1)

We have two points (2, -2) and (4, -1).

Substitute:

m=(-1-(-2))/(4-2)=(-1+2)/(2)=(1)/(2)

Put the value of a slope and the coordinates of the point (2, -2) to the equation of a line:

-2=(1)/(2)(2)+b

-2=1+b subtract 1 from both sides

$-3=b\to b=-3$

Finally:

y=(1)/(2)x-3