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A 0.32 kg turntable of radius 0.18 m spins about a vertical axis through its center. A constant rotational acceleration causes the turntable to accelerate from 0 to 24 revolutions per second in 8.0 s. [Hint: model the turntable has a uniform density disk.] What is the rotational acceleration of the turntable

User Cordelia
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1 Answer

7 votes

Answer:
18.85 rad/s^2

Step-by-step explanation:

Given

mass of turntable
m=0.32 kg

radius
r=0.18 m


N=24 rev/s


\omega =2\pi N=2\pi 24


\omega =48\pi rad/s

time interval
t=8 s

using
\omega =\omeag _0+\alpha t

where
\omega =final\ angular\ velocity


\omega _0=initial\ angular\ velocity


\alpha =angular\ acceleration


t=time


48\pi =0+\alpha * 8


\alpha =6\pi rad/s^2


\alpha =18.85 rad/s^2

User Soravux
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