Answer:
λ = 547.96 nm
Step-by-step explanation:
given,
thickness of soap bubble = 103 nm
refractive index of thin film = 1.33
using formula of constructive interference

t is thickness of the medium
n is refractive index
m = 0,1,2...
now,

at m = 0

λ = 547.96 nm
at m = 1


λ = 182.65 nm
the only visible light enhanced by the thin film is of wavelength
λ = 547.96 nm