Question

A jet aircraft is traveling at 201 m/s in horizontal flight. The engine takes in air at a rate of 44.1 kg/s and burns fuel at a rate of 3.28 kg/s. The exhaust gases are ejected at 669 m/s relative to the aircraft. Find the thrust of the jet engine. Answer in units of N.

Answer 1

Answer:22,833.12 N

Step-by-step explanation:

Given

Velocity of Jet
`v=201 m/s`

Velocity of Exhaust gases
`u=669 m/s`

Rate of intake of air
`\frac{\mathrm{d} M_a}{\mathrm{d} t}=44.1 kg/s`

Rate at which Fuel is burned is
`\frac{\mathrm{d} M_f}{\mathrm{d} t}=3.28 kg/s`

Rate of change of mass in Rocket
`\frac{\mathrm{d} M}{\mathrm{d} t}=\frac{\mathrm{d} M_a}{\mathrm{d} t}+\frac{\mathrm{d} M_f}{\mathrm{d} t}=44.1+3.28=47.38 kg/s`

Thrust on Rocket is given by

`F=\frac{\mathrm{d} M}{\mathrm{d} t}u-\frac{\mathrm{d} M_a}{\mathrm{d} t}v`

`F=47.38* 669-44.1* 201`

`F=31,697.22-8864.1=22,833.12 N`