Question

The perimeter of a rectangle is twice the sum

of its length and its width. The perimeter is
40 meters and its length is 2 meters more
than twice its width.

Answer 1

The width of the given rectangle = 6 m

The width of the rectangle = 14 m

Explanation:

Let us assume the width of the rectangle = k

So, the length of the rectangle = 2 + 2 ( The width) = 2 + 2 k

Perimeter of the rectangle = 40 meters

Now, PERIMETER OF THE RECTANGLE = 2(LENGTH + WIDTH)

or, 40 = 2 ( k + (2 + 2 k))

⇒ 2( 3 k + 2) = 40

or, 2(3 k) + 2(2) = 40

or, 6 k = 40 - 4 = 36

⇒ k = 36 / 6 = 6, or k = 6

Hence, the width of the given rectangle = k = 6 m

The width of the rectangle = 2 + 2 k = 2 + 2(6) = 14 m