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What is the image point of (-12, -8) after the transformation R270° 0 D. ?

What is the image point of (-12, -8) after the transformation R270° 0 D. ?-example-1

2 Answers

1 vote

Answer: -2,3

Explanation:

User Aldith
by
3.4k points
7 votes

Given:

The point is (-12,-8).

Rule of transformation is
R_(270^\circ)\circ D_{(1)/(4)}.

To find:

The coordinates of image after transformation.

Solution:

According to the rule of transformation
R_(270^\circ)\circ D_{(1)/(4)}, first the point is dilated by factor
(1)/(4) with origin as center of dilation after that it was rotated 270 degrees anticlockwise.

If a point is dilated by factor
(1)/(4) with origin as center of dilation, then


(x,y)\to \left((1)/(4)x,(1)/(4)y\right)


(-12,-8)\to \left((1)/(4)(-12),(1)/(4)(-8)\right)


(-12,-8)\to \left(-3,-2\right)

If a point is rotated 270 degrees anticlockwise, then


(x,y)\to (y,-x)


(-3,-2)\to ((-2),-(-3))


(-3,-2)\to (-2,3)

Therefore, the coordinates of image after transformation are (-2,3).