Question

Find the area and the perimeter of a rectangle with a length of 2√7 feet and a

width of 10√7 feet.

Answer 1

see explanation

Explanation:

the area (A) of a rectangle is calculated as

A = lw ( l is the length and w the width )

using the property
`√(a)` ×
`√(a)` = a , then

A = 2
`√(7)` × 10
`√(7)`

= 2 × 10 ×
`√(7)` ×
`√(7)`

= 20 × 7

= 140 ft²

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the perimeter (P) is calculated as

P = 2(l + w)

= 2(2
`√(7)` + 10
`√(7)` )

= 2(12
`√(7)` )

= 24
`√(7)` ft