Question

50 mL of a chlorofluorocarbon gas effused through a porous barrier in 157 seconds. The same volume of argon effused in 76 seconds under the same conditions. What is the formula of the chlorofluorocarbon?

Answer 1

`CCl_(2)FCF_(3)`

Step-by-step explanation:

To solve this equation we can use Graham's Law of effusion to calculate the molar mass of the chloroflourocarbon

`\sqrt{(M_(1) )/(M_(2) ) } = (t_(1) )/(t_(2) ) \\\\\sqrt{(M_(1) )/(39.948 ) } = (157 )/(76)\\\\\\M_(1)  = 170.477\\`

Which chloroflorocarbon has this molar mass?

C2Cl2F4