Question

find the equation of a line that is perpendicular to the given line and passes through the given point. enter your answer in slope intercept form y=mx+b with the values of m and b given as decimals, rounded to the nearest hundredth. y =10x ; (8,-2)

Answer 1

m= -0.1

b= -1.2

Explanation:

The equation of the given line is

y=10x, slope of the given line is 10.

As the line is perpendicular to this line, the slope is
`-(1)/(10)`

m= -0.1

( product of slope of two perpendicular lines is -1)

thus the equation is

`y = (-(1)/(10))x + b`

`y = (-0.1)x + b`

now to find the value of b, input the point coordinates (8, -2) in the above equation.

`-2 = (-0.1)(8) + b`

`b = -2 + (0.8)`

b = -1.2