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Which are the solutions of x2 = –13x – 4? 0, 13 0, –13 StartFraction 13 minus StartRoot 153 EndRoot Over 2 EndFraction comma StartFraction 13 + StartRoot 153 EndRoot Over 2 EndFraction StartFraction negative 13 minus StartRoot 153 EndRoot Over 2 EndFraction comma StartFraction negative 13 + StartRoot 153 EndRoot Over 2 EndFraction

User Grifball
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2 Answers

5 votes

Answer:


x_(1)=(-13+√(153))/(2)\\x_(2)=(-13-√(153))/(2)

Explanation:

The given expression is


x^(2)=-13x-4

To solve this quadratic equation, we first need to place all terms in one side of the equation sign


x^(2) +13x+4=0

Now, to find all solutions of this expression, we have to use the quadratic formula


x_(1,2)=\frac{-b\±\sqrt{b^(2)-4ac}}{2a}

Where
a=1,
b=13 and
c=4

Replacing these values in the formula, we have


x_(1,2)=\frac{-13\±\sqrt{(13)^(2)-4(1)(4)}}{2(1)}\\x_(1,2)=(-13\±√(169-16))/(2)=(-13\±√(153))/(2)

So, the solutions are


x_(1)=(-13+√(153))/(2)\\x_(2)=(-13-√(153))/(2)

If we approximate each solution, it would be


x_(1)=(-13+√(153))/(2)\approx -0.32\\\\x_(2)=(-13-√(153))/(2) \approx -12.68

User Momeneh Foroutan
by
5.1k points
5 votes

Answer:

D on Edge

Explanation:

User Sovas
by
5.5k points