Question

PLEASE HELP!!!!!!!! y+1=1/3(x−3) how do i graph this? what are the points?

Answer 1

Explanation:

You have the equation of a line in the point-slope form:

`y-y_1=m(x-x_1)`

m - slope

(x₁, y₁) - point on a line

Convert the given equation to the slope-intercept form:

`y=mx+b`

m - slope

b - y-intercept (0, b)

`y+1=(1)/(3)(x-3)` use the distributive property

`y+1=(1)/(3)x-1` subtract 1 from both sides

`y=(1)/(3)x-2`

We only need two points to draw the line.

Choose two different x values. Put them in the line equation and calculate the y values:

for x = 0:

`y=(1)/(3)(0)-2=0-2=-2\to(0,\ -2)`

for x = 3:

`y=(1)/(3)(3)-2=1-2=-1\to(3,\ -1)`