Question

A loop of wire enclosing an area of 0.19 m2 has a magnetic field passing through its plane at an angle to the plane. The component of the field perpendicular to the plane is 0.5 T and the component parallel to the plane is 0.8 T. What is the magnetic flux through this coil? Round the final answer to three decimal places.

Answer 1

To solve this exercise it is necessary to apply the concepts related to Magnetic Flow which is defined through the Gaus Law of Magnetism as the measure of the total magnetic field that passes through a given area.

Vectorially it can be defined as

`\Phi = \vec{A}\vec{B}`

Where,

A = Area

B = Magnetic Field

A scalar mode can also be expressed as

`\Phi = A*B Cos\theta`

Where,

`\theta` is the angle between B and A, at this case the direction are perpendicular then

Our values are given as,

`A = 0.19m^2`

`B_1 = 0.5T`

`B_2 = 0.8T`

The magnetic field component that interests us is the perpendicular therefore

`\Phi = 0.19* 0.5cos(90)`

`\Phi = 0.095Tm^2`

Therefore the magnetic flux through this coil is 0.095
`Tm^2`