Question

How many grams of hydrogen must react if the reaction needs to produce 31.75 g of NH3

Answer 1

5.603 g H2

Explanation:

M(NH3) = 14 + 1*3 = 17 g/mol

M(H2) = 2*1 = 2 g/mol

3H2 + N2 -----> 2NH3

from reaction 3 mol 2 mol

from reaction 3*2 g 2*17 g

given x g 31.75 g

We can write a proportion.

(3*2)/x = 2*17/31.75

(2*17)x = (3*2)*31.75

x = (3*2)*31.75/(2*17) = 3*31.75/17 =5.603 g H2