Question

If 21.39 g  acetylene is allowed to completely react with oxygen, how many grams of O2 are reacted? (The molar mass of acetylene is 26.04 g/mol)2 C2H2(g) + 5 O2(g) → 4 CO2(g) + 2 H2O(g)acetyleneBe sure to use the p

Answer 1

65.712 grams of oxygen has reacted.

Step-by-step explanation:

`2 C_2H_2(g) + 5 O_2(g)\rightarrow 4 CO_2(g) + 2 H_2O(g)`

Mass of acetylene = 21.39 g

Moles of acetylene =
`(21.39 g)/(26.04 g/mol)=0.8214 mol`

According to reaction , 2 moles of acetylene reacts with 5 moles of oxygen gas.

Then 0.8214 moles of oxygen gas will react with :

`(5)/(2)* 0.8214 mol=2.0535 mol` of oxygen gas.

Mass of 2.0535 moles of oxygen gas :

2.0535 mol × 32 g/mol = 65.712 g

65.712 grams of oxygen has reacted.