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A weight watcher who normally weighs 400 N stands on top of a very tall ladder so she is one Earth radius above Earth's surface (i.e. twice her normal distance from Earth's center). How much is her weight there? Group of answer choices

User AB Vyas
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5.4k points

2 Answers

6 votes

Answer: It Would Be 100 N

Step-by-step explanation:

User Michelina
by
5.6k points
1 vote

Answer:

100 N

Step-by-step explanation:

Let us first find the mass of the person when they are on the earth's surface


F=G(Mm)/(r^(2) )\\

Now let us see how F changes if the distance between two masses is doubled


F_(1)  = G(Mm)/((2r)^(2) ) = (1)/(4) *G(Mm)/(r^(2) )

So when the distance of separation is doubled, the force of gravity between the two masses decreases by a factor of four

Therefore her new weight = 400 N/4 = 100 N

User Mwek
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5.1k points