Question

A block of mass 2.20 kg is placed against a horizontal spring of constant k = 825 N/m and pushed so the spring compresses by 0.0650 m. HINT (a) What is the elastic potential energy of the block-spring system (in J)?

Answer 1

Answer:1.742 J

Step-by-step explanation:

Given

mass of block
`m=2.2 kg`

`k=825 N/m`

Compression in spring
`x=0.065 m`

Elastic Potential Energy of the Spring-mass system is given by

`E=(1)/(2)kx^2`

where
`k=spring\ constant`

`x=compression\ in\ spring`

`E=(1)/(2)* 825* (0.065)^2`

`E=412.5* 42.25* 10^(-4)`

`E=1.742 J`