Question

A student sees her physical science professor approaching on the sidewalk that runs by her dorm. She gets a water balloon and waits. When the professor is 2 s from being directly under her window 11 m above the idewalk, she drops the balloon. You finish the story. (Assume g # 10 m/s*)

Answer 1

Answer:Misses the Target

Step-by-step explanation:

Given

Distance between window and Professor is h=11 m

she dropped the balloon 2 sec earlier

time taken by balloon to cover the 11 m

using

`h=ut+(at^2)/(2)`

where h=height

u=initial velocity

t=time

a=acceleration

`11=0+(9.8t^2)/(2)`

`t=\sqrt{(2* 11)/(10)}`

`t=√(2.2)`

`t=1.483 s`

Therefore she misses the Professor by 0.51 s