Answer:
102.807 kPa
Step-by-step explanation:
There are some assumptions to be made in the answer. The air inside the balloon acts as an ideal gas at a given temperature conditions.
Using the combined ideal gas equation.
![PV = nRT\\](https://img.qammunity.org/2020/formulas/chemistry/high-school/hvpo6eo5k49i9y15la3lbg888p3k0mbned.png)
P= absolute pressure of air inside the balloon.
V= volume of air inside the balloon (6.23 L= 6.23 * 10⁻³ m³)
n= moles of gas(air). (0.250 mol)
R= Universal gas constant ( 8.314 J / mol·K)
T= Temperature in Kelvin
T= 35 + 273.15 = 308.15 K
So,
![P = (nRT)/(V)](https://img.qammunity.org/2020/formulas/physics/high-school/uhngg8o66un8k0bo8z9bw8jb2c2iln6mlt.png)
![P = (0.250 * 8.314 * 308.15)/(6.23 * 10^(-3) )](https://img.qammunity.org/2020/formulas/chemistry/middle-school/5wcp2dh5jt71053iuzwt6uzrpwmn5d38g8.png)
P= 102.807 * 10³ Pa
P= 102.807 kPa