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A balloon is filled with 0.250 mole of air at 35°C. If the volume of the balloon is 6.23 liters, what is the absolute pressure of the air in the balloon? The absolute pressure of the air in the balloon is kilopascals.

2 Answers

4 votes

Answer: 103 for Edmentum users !

User Planarian
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6 votes

Answer:

102.807 kPa

Step-by-step explanation:

There are some assumptions to be made in the answer. The air inside the balloon acts as an ideal gas at a given temperature conditions.

Using the combined ideal gas equation.


PV = nRT\\

P= absolute pressure of air inside the balloon.

V= volume of air inside the balloon (6.23 L= 6.23 * 10⁻³ m³)

n= moles of gas(air). (0.250 mol)

R= Universal gas constant ( 8.314 J / mol·K)

T= Temperature in Kelvin

T= 35 + 273.15 = 308.15 K

So,
P = (nRT)/(V)


P = (0.250 * 8.314 * 308.15)/(6.23 * 10^(-3) )

P= 102.807 * 10³ Pa

P= 102.807 kPa

User Matei Radu
by
5.8k points