Answer:
The factory must produce 6,400 parts so that there is 1 ton of scrap aluminum for recycling.
Explanation:
1 part produced ⇒ 5 ounces scrap aluminium recycled.
So, the ratio of parts produced : Scrap of aluminium = 1 : 5 .... (a)
Let us assume for m parts produced , 1 ton of scrap is recycled.
Also, 1 ton = 2, 000 pounds
and 1 pound = 16 ounces
⇒ 1 ton = 2000 x (16 ounces) = 32,000 ounces
So, for m parts made in the factory, 32,000 ounces scrap is recycled.
So, the ratio of parts produced : Scrap of aluminium = m : 32,000 .... (b)
From both the given ratio, we get
1 : 5 = m : 32,000
or,
![(1)/(5) = (m)/(32,000) \implies m = (32,000)/(5) = 6,400](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e9vfg2wnf0xpwlu6solz2jvkdixc8x1seg.png)
⇒ m = 6,400
Hence, the factory must produce 6,400 parts so that there is 1 ton of scrap aluminum for recycling.