Answer: Option (A) is the correct answer.
Step-by-step explanation:
It is known that relation between pressure, density, height, and gravity is as follows.
P =
![\rho * g * h](https://img.qammunity.org/2020/formulas/chemistry/high-school/9h937s4vrp6xqsd5gemgcqila5pizim6bx.png)
As it is given that pressure of both mercury and water column are equal. Therefore,
![\rho_(Hg) * g * h_(Hg) =\rho_{H_(2)O} * g * h_{H_(2)O}](https://img.qammunity.org/2020/formulas/chemistry/high-school/nel3lexpwb4lzvddbjm9qjgpmk26hgcysw.png)
Cancelling the common terms in the formula. Now, putting the given values into the above formula as follows.
![\rho_(Hg) * g * h_(Hg) =\rho_{H_(2)O} * g * h_{H_(2)O}](https://img.qammunity.org/2020/formulas/chemistry/high-school/nel3lexpwb4lzvddbjm9qjgpmk26hgcysw.png)
![13.6 g/cm^(3) * 256 mm = 1 * h_{H_(2)O}](https://img.qammunity.org/2020/formulas/chemistry/high-school/bgglloj592qwusmz4dx2rp3qe4klo40swo.png)
3481.6 mm =
![h_{H_(2)O}](https://img.qammunity.org/2020/formulas/chemistry/high-school/15ng9o57lnndh2wtim9njhdtmhgletcx2n.png)
As 1 mm = 0.1 cm
![3481.6 mm * (0.1 cm)/(1 mm)](https://img.qammunity.org/2020/formulas/chemistry/high-school/x6r3wggbki1nb1bh8a5oanz1x6c0fmalca.png)
= 348.1 cm
or, = 348 cm (approx)
thus, we can conclude that height of the given column is 348 cm.