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1 vote
A car and driver weighing 7130 N passes a sign stating...?

"Bridge Out 32 m Ahead." She slams on the brakes, and the car decelerates at a constant rate of 13.8 m/s^2. The acceleration of gravity is 9.8 m/s^2.
What is the magnitude of the work done stopping the car if the car just stops in time to avoid diving into the water?

User Saxman
by
5.5k points

2 Answers

3 votes

Answer:

321 280

Step-by-step explanation:

Work done = force * distanceThe distance is 32 mThe force can be calculated using the second law of motionF = ma = (7130 N ÷ 9.8 m/s²) * 13.8 m/s² = 10 040 NWork done = force * distance = 10 040 N * 32 m = 321 280 J

User Francene
by
5.0k points
4 votes

Answer:

321 280 J

Step-by-step explanation:

Work done = force * distance

The distance is 32 m

The force can be calculated using the second law of motion

F = ma = (7130 N ÷ 9.8 m/s²) * 13.8 m/s² = 10 040 N

Work done = force * distance

= 10 040 N * 32 m

= 321 280 J