Question

A person with mass mp = 71 kg stands on a spinning platform disk with a radius of R = 1.62 m and mass md = 193 kg. The disk is initially spinning at ω = 1.8 rad/s. The person then walks 2/3 of the way toward the center of the disk (ending 0.54 m from the center). 1)What is the total moment of inertia of the system about the center of the disk when the person stands on the rim of the disk?

Answer 1

439.587 kgm²

Step-by-step explanation:

`m_p` = Mass of person = 71 kg

R = Radius of platform = 1.62 m

`m_d` = Mass of disc = 193 kg

The moment of inertia of the system is given by

`I=m_pR^2+(1)/(2)m_dR^2\\\Rightarrow I=71* 1.62^2+(1)/(2)* 193* 1.62^2\\\Rightarrow I=439.587\ kgm^2`

The total moment of inertia of the system about the center of the disk when the person stands on the rim of the disk is 439.587 kgm²