Question

At an amusement park, the wheelie carries passengers in a circular path of radius r = 11.2 m. If the angular speed of the wheelie is 0.550 revolutions/s, (a) What is the tangential velocity of the passengers due to the circular motion? (b) What is the acceleration of the passengers?

Answer 1

(a) Tangential velocity will be 38.648 m/sec

(b) Acceleration will be
`133.617m/sec^2`

Step-by-step explanation:

We have given radius r = 11.2 m

Angular speed
`\omega =0.550rev/sec=0.550* 2\pi =3.454rad/sec`

(a) We have to find the tangential velocity

We know that tangential velocity is given by

`v_t=\omega r=3.454* 11.2=38.684m/sec`

(b) We know that acceleration is given by

`a=(v^2)/(r)=(38.684^2)/(11.2)=133.617m/sec^2`