Two boats leave a dock together . Each travels in a straight line . The angle between their courses measures 54° 10¢ . One boat travels 36.2 km/hr and the other travels 45.6 km/…

Question

asked Sep 12, 2020 34.9k views

1 Answer

Jonny Schubert · Answer 1 · 2020-09-15T21:57:42+0000

Answer:

218.93 km

Step-by-step explanation:

$\theta$ = Angle between the paths of the two boats = 54.10°

Distance = Speed × Time

Distance traveled by one boat =
$36.2* 3\ km$

Distance traveled by other boat =
$45.6* 3\ km$

From the triangle law of vectors we have

$d=√((36.2* 3)^2+(45.6* 3)^2+2* 36.2* 3* 45.6* 3* cos54.10)\\\Rightarrow d=218.93\ km$

The distance they will be apart after 3 hours is 218.93 km