Question

Two boats leave a dock together . Each travels in a straight line . The angle between their courses measures 54° 10¢ . One boat travels 36.2 km/hr and the other travels 45.6 km/hr. How far apart will they be after three hours

Answer 1

218.93 km

Step-by-step explanation:

`\theta` = Angle between the paths of the two boats = 54.10°

Distance = Speed × Time

Distance traveled by one boat =
`36.2* 3\ km`

Distance traveled by other boat =
`45.6* 3\ km`

From the triangle law of vectors we have

`d=√((36.2* 3)^2+(45.6* 3)^2+2* 36.2* 3* 45.6* 3* cos54.10)\\\Rightarrow d=218.93\ km`

The distance they will be apart after 3 hours is 218.93 km