Question

A 0.15 kg baseball is hit by a baseball bat. Right before it is hit, the ball’s speed is 30 m/s, and right after it is hit, the ball’s speed is 50 m/s in the opposite direction. What is the magnitude of the net impulse that is applied to the ball?

10.5 kg?m/sA. 4.5 kg?m/sB. 12.0 kg?m/sC. 7.5 kg?m/sD. 3.0 kg?m/s

Answer 1

Impulse will be 12 kgm/sec

So option (b) will be correct option

Step-by-step explanation:

We have given mass of the baseball m = 0.15 kg

Ball speed before hit
`v_1=30m/sec`

Ball speed after hitting
`v_2=-50m/sec` ( negative direction due to opposite direction )

We have to find the impulse

We know that impulse is equal; to the change in momentum

So change in momentum =
`m(v_1-v_2)=0.15(30-(-50))=0.15* 80=12kgm/sec`

So option (b) will be correct option