Question

Solve x2 – 8x = 3 by completing the square. Which is the solution set of the equation?

(4 minus StartRoot 19 EndRoot comma 4 + StartRoot 19 EndRoot)
(4 minus StartRoot 11 EndRoot comma 4 + StartRoot 11 EndRoot)
(4 minus StartRoot 8 EndRoot comma 4 + StartRoot 8 EndRoot)
(4 minus StartRoot 3 EndRoot comma 4 + StartRoot 3 EndRoot)

Answer 1

its A

Explanation:

Answer 2

`(4-√(19),4+\sqrt{19)`

Explanation:

we have

`x^(2) -8x=3`

Divide the coefficient of term x by 2

`-8/2=-4`

Squared the number

`(-4)^2=16`

Adds the number 16 to the both sides

`x^(2) -8x+16=3+16`

`x^(2) -8x+16=19`

Rewrite as perfect squares

`(x-4)^(2)=19`

take square root both sides

`(x-4)=(+/-)√(19)`

`x=4(+/-)√(19)`

`x_1=4(+)√(19)`

`x_2=4(-)√(19)`

therefore

The solution set is

`(4-√(19),4+\sqrt{19)`