Question

A 23.7 kg kid slides down a

frictionless water slide at 47.2°.
What is her acceleration?
(Unit = m/s2)​

Answer 1

`\text { The acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^(2)`

Step-by-step explanation:

Mass of the kid 23.7 kg.

`\text { The kid is accelerating down at an angle is } 47.2^(\circ) .`

`^(\prime \prime) \mathrm{g}^(\prime \prime) \text { acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^(2)`

We need to find the acceleration of the kid,

We know that, Parallel force acted on the kid at an angle is

F = m × g × sinθ (F = ma)

m × a = m × g × sinθ

Now, substitute the given values in the above formula to find acceleration of the kid,

`23.7 * a=23.7 * 9.8 * \sin 47.2^(\circ)`

23.7 × a = 232.26 × 0.733

23.7 × a = 170.24

`a=(170.24)/(23.7)`

`a=7.18 \mathrm{m} / \mathrm{s}^(2)`

`\text { Therefore, acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^(2)`