Question

Write a syarem of linear equations that defines the verbal problem, and then answer the question.

a rectangular pasture has a perimeter of 1000 feet. the pastures length is 300 feet more than its width.

whats the area of the pasture?​

Answer 1

40,000 ft

Explanation:

The area of a rectangle is weight*length, and the perimeter is the sum og the four sides, which are 2 lengths sides ans 2 width sides, so:

area = w*l

perimeter = 2w + 2l

If the perimeter is 1000 ft:

2w + 2l = 1000

Also, the length is 300 ft more than width, so:

l = 300 +w

So, our system is:

2w + 2l = 1000 (equation 1)

l =300 + w (equation 2)

Son, we can solve it by replacing equation 2 in equation 1:

2w + 2(300 +w) = 2w + 600 + 2w = 4w + 600 = 1000

Now, subtract 600 in both sides:

4w + 600 - 600 = 1000 - 600

4w = 400

Divide both sides by 4:

4w/4 = 400/4

w = 100

Lets replace this w value in equation 2 to find l:

l = 300 + 100 = 400, so l=400

Finally we can find the area using the area formula:

area = 400*100 = 40,000 ft2

So, the area is 40,000 ft2