Question

3(x^2+4x)+4(y^2-2y)=32

Answer 1

3x^2 + 12x + 4y^2 - 8y = 32

Explanation:

3(x^2+4x)+4(y^2-2y)=32

At first we have to break the parenthesis to get the variables in normal position. To break those, we have to multiply each with the help of algebraic expression:

or, (3*x^2) + (3 × 4x) + (4 × y^2) - (4 × 2y) = 32

or, 3x^2 + 12x + 4y^2 - 8y = 32

Since the equation does not have anything to add or deduct, therefore, it is the answer.