Answer:
2x² + 2x + 3
Explanation:
x = 3 is a zero of both the numerator and the denominator, so the denominator will factor completely into the numerator with no remainder. Using grouping to factor:
(2x³ − 4x² − 3x − 9) / (x − 3)
(2x³ − 4x² − 6x + 3x − 9) / (x − 3)
(2x (x² − 2x − 3) + 3x − 9) / (x − 3)
(2x (x − 3) (x + 1) + 3 (x − 3)) / (x − 3)
2x (x + 1) + 3
2x² + 2x + 3
To use long division instead, see image.