Answer:
4y/(y+4)
Explanation:
2y/(y-3) x [(4y -12) /(2y+8)]
To determine this, at first we have to break the parentheses. Since there is no matching values, we have to multiply the numerators and denominators.
[2y x (4y - 12)] / (y-3) x (2y + 8)
or, [(2y*4y) - (2y*12)]/[(y*2y) + (y*8) - (3*2y) - (3*8)]
(using algebraic equation)
or, (8y^2 - 24y)/(2y^2 + 8y - 6y - 24)
or, (8y^2 - 24y)/(2y^2 + 2y - 24)
or, 8y(y - 3)/2(y^2 + y - 12) (taking common)
or, 4y(y - 3)/(y^2 + 4y - 3y - 12)
or, 4y(y - 3)/[y(y + 4) - 3 (y + 4)] (Using factorization or Middle-Term factor)
or, 4y (y - 3)/(y + 4)(y - 3)
or, 4y/(y + 4) [as (y-3)/(y-3) = 1, we have dropped the part]
The answer is = 4y/(y+4)