Answer:
A
![F(x)=-(1)/(1500)(x+20)(x+5)(x-15)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4zq91lsv8jzjput9akgnfqy75ng9m92fdq.png)
B
![=> F(x)=-(x^3)/(1500)-(x^2)/(150)+(11x)/(60)+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dh3jglpvwkksrjvvmdk5pea4y6jtk2p9ag.png)
Explanation:
Function and its graphs
Part A
The graph shown in the image corresponds to a cubic function because of its classical infinite branches, three real roots and two extrema values
Part B
Knowing the value of the three roots x=-20, x=-5, and x=15 we can express the cubic function in factored form:
![F(x)=C(x+20)(x+5)(x-15)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/adn7lcjtulbz0p1vj2901xg4e6vbqxo7uo.png)
The value of C will be determined by using any particular point from the graph. Let's use (0,1)
![1=C(0+20)(0+5)(0-15)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d4r87qu7sc729v2hgs5ng1q7xasr9nic1e.png)
![C=-(1)/(1500)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gr39s70i2bl2aqkkmvh81rg8v00pdl8r2a.png)
Replacing, we find the factored form of the function
![F(x)=-(1)/(1500)(x+20)(x+5)(x-15)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4zq91lsv8jzjput9akgnfqy75ng9m92fdq.png)
The standard form demands to expand all the products and simplify
![F(x)=-(1)/(1500)(x^3+10x^2-275x-1500)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dtsor9l1w3an4wkn5f0isoshqmjqelis0l.png)
![=> F(x)=-(x^3)/(1500)-(x^2)/(150)+(11x)/(60)+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dh3jglpvwkksrjvvmdk5pea4y6jtk2p9ag.png)