Answer:
The solutions of the equation are t = 4(√5 + 1) or 4(√5 - 1).
Explanation:
We have to solve the given quadratic equation of single variable t.
The equation is 16 = 2t + 0.25t²
⇒ 0.25t² + 2t - 16 = 0
⇒ 25t² + 200t - 1600 = 0 {Multiplying both sides with 100}
⇒ 25t² + 200t + 400 - 400 - 1600 = 0
⇒ (5t + 20)² - 2000 = 0
⇒ (5t + 20)² - (20√5)² = 0
⇒ (5t + 20 + 20√5)(5t + 20 - 20√5) = 0
So, (5t + 20 + 20√5) = 0 or, (5t + 20 - 20√5) = 0
⇒ (t + 4 + 4√5) = 0 or, (t + 4 - 4√5) = 0
⇒ t = - 4(1 + √5) or, t = 4(√5 - 1) (Answer)