Question

What is the equation of the line that passes through point (4, 12) and has a intercept of -2​

Answer 1

`\large\boxed{y=(7)/(2)x-2}`

Explanation:

The slope-intercept form of an equation of a line:

`y=mx+b`

m - slope

b - y-intercept → (0, b)

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

We have the point (4, 12), and y-intercept b = -2 → (0, -2).

Substitute:

`m=(-2-12)/(0-4)=(-14)/(-4)=(14:2)/(4:2)=(7)/(2)`

Finally:

`y=(7)/(2)x-2`