184k views
0 votes
3 Consider the reaction :

Na + 3 H₂ ____2NH₂
suppose that at a particular moment during the reaction, molecular hydrogen
is reacting at the rate of 0,074 m/s a) At what rate is ammonia being formed? b) At
what is molecular nitrogen reacting

User Tobilocker
by
5.6k points

1 Answer

3 votes

Answer:

(a) The rate at which ammonia being formed = 0.0493 M/s

(b) The rate at which molecular nitrogen reacting = 0.0247 M/s

Step-by-step explanation:


N_(2)+3H_(2)\longrightarrow2NH_(3)

The rate at which molecular hydrogen is reacting =
(d)/(dt)[H_(2)]=0.074\:M/s

The rate of the above reaction can be expressed as:


rate=-(d)/(dt)[N_(2)]=-(1)/(3) (d)/(dt)[H_(2)]=(1)/(2)(d)/(dt)[NH_(3)]

(a)
(d)/(dt)[NH_(3)]=(2)/(3)(0.074)=0.0493

The rate at which ammonia being formed = 0.0493 M/s

(b)
-(d)/(dt)[N_(2)]=(1)/(3)(0.074)=0.0247

The rate at which molecular nitrogen reacting = 0.0247 M/s

User Adjan
by
4.9k points