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How many zeros does the function f(x)=3x^12 -17x^8+11x^4-6x+23 have

User Roseanne
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1 Answer

5 votes

Answer:

12.

Explanation:

The number of zeros to an equation is the highest power of the polynomial.

A quadratic equation whose highest degree is 2, has two solutions.

The equation f(x) =
$ 3x^(12) - 17x^(8) + 11x^(4) - 6x + 23 $ will have 12 solutions (or zeroes) since the highest degree is 12.

User SahalMoidu
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