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1 vote
Find the x- and y-intercepts for the linear equation.
– 3x + 5y = 15

User Logard
by
6.0k points

2 Answers

4 votes

Answer:

Explanation:

To find the x-intercept of – 3x + 5y = 15, let y = 0 and solve the remaining equation for x: – 3x + 5(0) = 15

Then -3x = 15, and x = -5. Thus, the x-intercept is (-5, 0).

to find the y-intercept of – 3x + 5y = 15, set x = 0 and solve the remaining equation for y: 5y = 15, so that y = 3. The y-intercept is (0, 3).

User Animal Rights
by
5.7k points
5 votes

Answer:

x-intercept: (-5,0)

y-intercept: (0,3)

Explanation:

y-intercept: when x = 0

-3(0) + 5y = 15

5y = 15

y = 3

x-intercept: when y = 0

-3x + 5(0) = 15

-3x = 15

x = -5

User Yoshiko
by
4.9k points